andylu321 发表于 2019-7-4 10:29:11

按键消 抖动 含单按 和 长按两种状态


单独按一次按钮启动一组动作   长时间按 启动另一组动作


const int buttonPin = 11;    // the number of the pushbutton pin
const int ledPin = 13;      // the number of the LED pin
int ledState = HIGH;         // the current state of the output pin
int buttonState;             // the current reading from the input pin
int lastButtonState = HIGH;   // the previous reading from the input pin
long lastDebounceTime = 0;// the last time the output pin was toggled
long debounceDelay = 50;    // the debounce time; increase if the output flickers
long debounceDelay2 = 1050;    // the debounce time; increase if the output flickers
int ttt;   
void setup() {
pinMode(buttonPin, INPUT_PULLUP);
pinMode(ledPin, OUTPUT);
digitalWrite(ledPin, ledState);
Serial.begin(9600);
}
void loop() {
int reading = digitalRead(buttonPin);//读取按键电平高低
if (reading != lastButtonState) {    //如果电瓶如之前翻转了.说明按键状态改变.
    lastDebounceTime = millis();      //记录翻转时候的时间
//   Serial.println("1111");
}

if ((millis() - lastDebounceTime) > debounceDelay)
{

    if (reading != buttonState) {
      buttonState = reading;
      if (buttonState == LOW) {
      ledState = !ledState;
      ttt++;
      Serial.println(ttt);
      }
    }
}
if ((millis() - lastDebounceTime) > debounceDelay2)
{
      if (reading == LOW) {
      Serial.println(ttt);
    }
}
   
digitalWrite(ledPin, ledState);
lastButtonState = reading;
}

lala5 发表于 2020-3-11 12:22:11

显示编译有误
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