求解~procesing 一直提示port com 17:port busy
以下是我的程序，我的端口没有占用，但是编译的时候一直会出现port busy这是为什么呢。import processing.serial.*;
Serial port;
void setup() {
size(256, 150);
println("Available serial ports:");
println(Serial.list());
// Uses the first port in this list (number 0).Change this to
// select the port corresponding to your Arduino board.The last
// parameter (e.g. 9600) is the speed of the communication.It
// has to correspond to the value passed to Serial.begin() in your
// Arduino sketch.
port = new Serial(this, Serial.list(), 9600);
// If you know the name of the port used by the Arduino board, you
// can specify it directly like this.
port = new Serial(this, "COM17", 9600);
}
void draw() {
// draw a gradient from black to white
for (int i = 0; i < 256; i++) {
stroke(i,0,0);
line(i, 0, i, 150);
}
// write the current X-position of the mouse to the serial port as
// a single byte
port.write(mouseX);
}
port = new Serial(this, Serial.list(), 9600);
这个时侯端口已打开了
然后你又用了
port = new Serial(this, "COM17", 9600);
当然提示端口被占用了。 jeffliu 发表于 2013-11-21 16:16 static/image/common/back.gif
port = new Serial(this, Serial.list(), 9600);
这个时侯端口已打开了
然后你又用了
那要实现功能要怎么改呢，求教 不二的文艺 发表于 2013-11-28 20:01 static/image/common/back.gif
那要实现功能要怎么改呢，求教
晕，把后面那个port = new Serial(this, "COM17", 9600);注释掉就好了呀。如果你确定端口是COM17，那么就把前面那个port = new Serial(this, Serial.list(), 9600); 注释掉。这两行代码只能有一行有效。
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