如何让开关触发，使0，1针脚给其他设备发送串口命令

charlieson

各位社区的大神们好，我是小白一个，没什么编程基础。有个需求搜了搜还不知道怎么做。详见图片：

Arduino通过0，1针脚用串口线和摄像机串口连接，通过开关点按触发Arduino开发板给摄像机发控制码，控制码是16进制数组，如：AA 64 02 01 02
按一次开关，触发给摄像机发送AA 64 02 01 02，第二次按发送AA 64 02 01 03，再次循环往复···
求问，如何编写代码实现，感谢。

i7456

int code1[] ={0xAA, 0x64, 0x02, 0x01, 0x02};
int code2[] ={0xAA, 0x64, 0x02, 0x01, 0x03};

// this constant won't change:
const int  buttonPin = 2;    // the pin that the pushbutton is attached to
const int ledPin = 13;       // the pin that the LED is attached to

// Variables will change:
int buttonPushCounter = 0;   // counter for the number of button presses
int buttonState = 0;         // current state of the button
int lastButtonState = 0;     // previous state of the button

void setup() {
  // initialize the button pin as a input:
  pinMode(buttonPin, INPUT);
  // initialize the LED as an output:
  pinMode(ledPin, OUTPUT);
  // initialize serial communication:
  Serial.begin(9600);
}


void loop() {
  // read the pushbutton input pin:
  buttonState = digitalRead(buttonPin);

  // compare the buttonState to its previous state
  if (buttonState != lastButtonState) {
    // if the state has changed, increment the counter
    if (buttonState == HIGH) {
      // if the current state is HIGH then the button went from off to on:
      buttonPushCounter++;
      if (buttonPushCounter % 2 == 0) {
        digitalWrite(ledPin, HIGH);
        for(int i = 0; i < 5; i++)
          Serial.print(code1);
        } else {
          digitalWrite(ledPin, LOW);
          for(int i = 0; i < 5; i++)
            Serial.print(code2);
        }
    }
    // Delay a little bit to avoid bouncing
    delay(50);
  }
  // save the current state as the last state, for next time through the loop
  lastButtonState = buttonState;

}

charlieson

i7456 发表于 2020-4-15 13:13
int code1[] ={0xAA, 0x64, 0x02, 0x01, 0x02};
int code2[] ={0xAA, 0x64, 0x02, 0x01, 0x03};

感谢大神回复，我找个板子接好刷进去试下。代码根据注释能看懂个八成左右，谢谢。